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// 2. 排序:逐个将堆顶元素放到末尾

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1 It’s also possible to use 4 candidates per pixel and compute the barycentric coordinates of the resulting tetrahedron, but using 3 candidates forming a triangle is more straightforward. ↑,这一点在爱思助手下载最新版本中也有详细论述

Less Than (2): Everything in this space must be less than 2. The answer is 6-0, placed horizontally.

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Вашингтон Кэпиталз,更多细节参见WPS官方版本下载